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THE ROOF LENGTH FROM CENTER OF EAVE GIRT TO CENTER OF RTDGE <br /> <br />C=29 ~000,000~, .0165 <br /> <br /> [2~( 1+.3):¢.1,..z ~,,.o~3/(L~ <br /> <br />Ch=c~(coS A)"2 <br /> <br />DETERMINE THE REL. AT,f. VE STIFFNESS OF FRAME TO ROOF <br /> <br />DETERM~:NE FrO AND his REDUCTION FACT~.RS FROM TABLE <br />BASED UPON THE STRUCTURE HAVING ~_ FRAMES. <br /> <br />i AND 2 <br /> <br />STEP 4: CALCULATE THE RESISTANCE FORCE TO S;[DESWAY AND SHEAR <br />FORCE IN ROOF CLADDING <br /> <br />VALUE OF CLADDING <br /> ,.HE, AR FORCE=mS *ROLL_ER REACTION FROM STEP <br />1. <br /> <br />STEP S.DISTRIBUTE THE SIS'TANCE FORCE TO SIDESWAY EQUALLY AT <br />TOP CHORD NODES OPPOSITE THE WIND LOADING ON THE:: WALLS <br /> oTRESSE$ INTERACTION VAL, UE = <br />THE~AXIMUM COMBINE ct- , . <br /> ¢~< i 0 THEREFORE 6X~IS O.K. <br /> <br />STEP 5:CHECK SHEAR IN ROOFING NEAR ENDWALLS. ROOF CLADDING <br />SHEAR FORCE(STEP 4)/~UZLDING WIDTH MUST BE LESS OR EQUAL TO <br /> <br />I~ ~ ,,/W IDTH_~.= ~<=liT.22PLF <br /> <br />CHECK ~HEAR TRANSFERRED TO ENDWALL OiAPHRAM. ROOF Ct.,,ADDING <br />SHEAR FORCE (STEP 4 } /E3UILDZNG WIDTH LESS DOOR OPENINGS MUST <br />BE LE,~S OR EQUAL 'fO USEABLE SMEAR FROM STEP 3 AD~ .~E[ FOR <br />LOAD DURATION ( 2 ,333) <br /> <br />~ END MINUS DOOR = USEABLE <br /> __ / ..... ~IOTH USEABLE = <br /> 4117,22PL. F' <br /> <br />NEED ~1 FT TO DEVELOP SHEAR IN END WALL <br /> <br /> <br />