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NOW DETERMINE k2 FROM LUTTRELL'S ~QRMULA <br /> · , .9-9~(~0~00 0.0165 <br /> Et ~'. ' ' ' ' * <br /> <br />[2(l+v)g/p+k2/(144,,,0.0165}^2]' [~,(1~0.~),~.2+k2/(144,.0165)^2] <br /> <br />k2 value ---- 2,542.78 :''. , :.. : : <br />THE ROOF SLOPE LENGTH FROM CENTER OF !THE ~.A~E ~T TO CENTER OF RIDGE <br />PURLIN, L= 185.54 INCHES <br /> 29,000t 000.*0.0165 <br /> C = .............................. = 1~ 743.61 <br /> [2*(l+.3)*l,2+k2/(L*.0165)^2] <br /> <br />Ch=C * (COS A)^2 * 2= 3,282.09 <br /> <br />DETERMINE THE RELATIVE STIFFNESS OF FRi%ME TO ROOF <br /> ~/ch = 0.0728 <br /> <br />DETERMINE mD i%ND ms REDUCTION FACTORS FROM TABLES 1 AND 2 <br />(GEEREMEDHIN PGS. 1366-1367) BASED UPON THIS STRUCTURE HAVING <br />5 FRAMES INCLUDING THE ENDWALLS. <br /> <br />mD= 0.9324 ~S= 0.9324 <br /> <br />STEP ~4: CALCULATE THE RESIATANCE FORCE TO SIDESWAY AND SHEAR FORCE <br />IN THE ROOF CLADDING. <br />RESISTANCE FORCE TO SIDEWAY = mD * ROLLER REACTION (from step#l) <br /> 0.9324 * 903.34 = 842.32 <br />ROOF CLADDING SHEAR FORCE = ~S * ROLLER REACTION <br /> 0.9324 * 903.34 = 842.32 <br /> <br />STEP#5 : DISTRIBUTE THE RESISTANCE FORCE TO SIDESWA¥ EQUALLY AT THE <br />TOP CHORD NODES OPPOSITE THE WIND LOADING ON THE WALLS. <br /> NUMBERS OF NODES: 5 <br />RESISTANCE FORCE/No. of NODES= 168.46 lbs.~EACH NODE <br /> <br />THE MAXIMUM COMBINED STRESSES INTERACTION VALUE= <br /> <1.0 <br />THEREFORE <br /> <br />STEP #6: CHECK SHEAR IN ROOFING NEAR ENDWALLS. <br />ROOF CLADDING SHEAR FORCE (STEP #4)/BUILDING WIDTH MUST BE LESS OR <br />EQUAL TO THE ADJUSTED SHEAR (V) FROM STEP #3 ADJUSTED FOR LOAD <br />DURATION (1.3333) <br /> 842.32 / 30.00 = 2a.0$ plf. <br /> 28.08 < (87.92,1.3333)= 117.22 <br /> 28.08 < 117.22 <br /> <br />CHECK SHEAR TRANSFERRED TO ENDWALL DIAPHGRAM. <br />ROOF CLADDING SHEAR FORCE (STEP #4)/BUILDING WIDTH LESS DOOR <br />OPENINGS MUST BE LESS OR EQUAL TO USEABLE SHEAR FROM STEP #3 <br />ADJUSTED FOR THE ON CENTER SPACING OF THE ENDWALL GIRTS ADJUSTED FOR <br />LOAD DURATION (1.3333) <br />ENDWALL -DOOR OPNGS(s 30.00 fT. USEABLE <br /> 84~.32 / 30.00 = 28.08 <br /> <br /> <br />